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„π°√≥’∑’˪√–™“°√∑—Èß 2 °≈ÿࡉ¡à‡ªìπÕ‘ √–µàÕ°—π
                                                              b
                                                      OR =
                                                                 c
                                                                 1   1
                                               SE(ên OR) =         +
                                                                     b  c


                           µ—«Õ¬à“ß∑’Ë 7.6


                                  „π°“√»÷°…“°“√«‘®—¬‡™‘ß«‘‡§√“–Àå·∫∫¿“§µ—¥¢«“ß (cross-sectional analytical
                           study) ‡æ◊ËÕ¥Ÿ«à“¿“«–´÷¡‡»√â“¢ÕßÀ≠‘ß«—¬∑”ß“π¡’§«“¡ —¡æ—π∏å°—∫Õ“¬ÿÀ√◊Õ‰¡à  ‚¥¬·∫àßÕ“¬ÿ
                           ÕÕ°‡ªìπ 2 °≈ÿà¡ §◊Õ °≈ÿà¡Õ“¬ÿ  20-40 ªï  ·≈– 41-60 ªï  º≈°“√ ”√«®· ¥ß„πµ“√“ß
                           µàÕ‰ªπ’È ®ß √ÿªº≈°“√»÷°…“



                                                                   ¿“«–´÷¡‡»√â“
                                        °≈ÿà¡Õ“¬ÿ (ªï)
                                                        ´÷¡‡»√â“      ª°µ‘         √«¡

                                          41-60           15           65          80
                                          20-40            5          115          120

                                           √«¡            20          180          200


                                  §”π«≥§à“ OR „π°√≥’∑’˪√–™“°√∑—Èß 2 °≈ÿࡇªìπÕ‘ √–µàÕ°—π

                                                         ad     115  ¥  15
                                                 OR =        =           =  5.3
                                                           bc        5 ¥  65
                                  ®“°§à“ OR ∑’ˉ¥â· ¥ß«à“§à“ Odds ¢Õß¿“«–´÷¡‡»√â“¢ÕßÀ≠‘ß«—¬ 41-60 ªï

                            Ÿß‡ªìπ 5.3 ‡∑à“¢Õß°≈ÿà¡À≠‘ß«—¬ 20-40 ªï
                                  °“√ª√–¡“≥§à“ OR ∑”‰¥â‚¥¬„™â Ÿµ√
                                   ên[(1 - Ò) ™à«ß§«“¡‡™◊ËÕ¡—Ëπ¢Õß OR]  =  ên(OR) £  Z SE(ên OR)
                                                                                a
                                                                                     2
                                  π”¢âÕ¡Ÿ≈¡“§”π«≥§à“ 95% ™à«ß§«“¡‡™◊ËÕ¡—Ëπ¢Õß OR ‰¥â¥—ßπ’È



                                       15   65                        1   1   1   1
                                                     SE(ên OR) =        +   +   +
                                       5    115                           a  b  c  d

                                                                       1    1   1    1
                                                                 =       +    +   +
                                                                          15  65  5  115
                                                                 = 0.539



                                                           7.3  °“√ª√–¡“≥§à“¢π“¥¢Õß§«“¡ —¡æ—π∏å  133





          ∫∑∑’Ë 7                  133                                   29/7/09, 4:13 PM
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