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„π°√≥’°“√∑¥ Õ∫ ¡¡µ‘∞“π∑’˰”Àπ¥„Àâ ˆ =ˆ
1 2
b + c
§«“¡§≈“¥‡§≈◊ËÕπ¡“µ√∞“π SE =
(p - p )
1 2 n
„π°√≥’°“√ª√–¡“≥§à“‰¡à‰¥â °”Àπ¥„Àâ ˆ =ˆ
1 2
1 (b - ) c 2
§«“¡§≈“¥‡§≈◊ËÕπ¡“µ√∞“π SE = (b + ) c -
(p - p )
1 2 n n
‡¡◊ËÕµ√«® Õ∫·≈â««à“¢π“¥µ—«Õ¬à“ß„À≠àæÕ‚¥¬¥Ÿ«à“§à“ b + c fl 20 ´÷Ëß∑”„Àâ
(p - p ) ¡’°“√·®°·®ßª°µ‘ ®÷ß„™â§à“ ∂‘µ‘ Z „π°“√ª√–¡“≥§à“·≈–‡ª√’¬∫‡∑’¬∫§à“ —¥ à«π
1 2
¢Õߪ√–™“°√¥â«¬ Ÿµ√¥—ßπ’È
°“√∑¥ Õ∫ ¡¡µ‘∞“π
È b - c ˘
-
Í ˙ [ p 1 - p 2 ]
Z= Î n ˚
b + c
n
‡æ√“– H : p = p
b - c n 0 1 2
= ë í Ó ë í p - p = 0 µ—¥ÕÕ°®“°
n b + 1 2
c
°“√§”π«≥
b - c
Ÿµ√°√≥’‰¡àª√—∫·°â§«“¡µàÕ‡π◊ËÕß Z =
b + c
b - c - 1
Ÿµ√°√≥’ª√—∫·°â§«“¡µàÕ‡π◊ËÕß Z =
b + c
b - c
Ÿµ√ª√–¡“≥§à“™à«ß§«“¡‡™◊ËÕ¡—Ëπˆ - ˆ = £
1 2
n
1 ( b - ) 2
c
Z a b + c -
n n
2
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∫∑∑’Ë 6 111 29/7/09, 2:25 PM